I am trying to take one date away from another in C and find the difference between them in days.However this is much more complicated than it first appeared to me as I obviously have to allow for differing days in different years due to leap years and a differing numbers of days depending on which month it is.
Current my data is stored as integers in array, for example,{21/1/1996 to 20/6/1996}
So could someone please post or point me towards an algorithm that will help me achieve this task?Thank you very much.
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/*write a program to find out the difference in days between any two dates*/
/*Written by Utpal Chaudhary*/
/* Student of L.D COLLEGE OF ENGINEERING, Navrangpura, Ahmedabad-15 */
#include<stdio.h>
#include<conio.h>
void main( )
{
int month[12]={31,28,31,30,31,30,31,31,30,31,30,31}; /* Here n=28 if year is not leap otherwise n=29 */
int i ,y ,d1, d2, m1, m2, total days=0;
printf (“Enter Year:”);
scanf (“%d”,&y);
if ( ( y%4 =0 && y%100!=0) || (y%400==0 ) ) month[1]=29;
printf (“Enter first date: (day and month )”);
scanf (“%d %d”,&d1,M1);
printf (“Enter Second date:(day and month)”);
scanf(“%d %d”,&d2,&m2);
totaldays=totaldays + month[m1-1]-d1;
for(i=m1, i<m2, i++)
{
totaldays=totaldays +month[i];
}
totaldays = totaldays + d2;
printf (“Total days = %d \n “,totaldays);
}
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Enter year:1996
Enter first date : (day and month)
21 1
Enter second date : (day and month)
20 6
Total days : 151
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