Design of Turnbuckle

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screw joint
Fig. 2 screw joint

Design of Turnbuckle :

Consider a turnbuckle, subjected to an axial load P, as shown in Fig. 1. Due to this load, theĀ threaded rod will be subjected to tensile stress whose magnitude is given by

Ļƒt = P / A

Ā  Ā  Ā = P / [{Ļ€ (dc)^2} / 4]

where dc = Core diameter of the threaded rod.

Turnbuckle
Fig. 1 Turnbuckle

In order to drive the rods, the torque required is given by

T = P tan (Ī± + Ļ†) dp/2

where Ī± = Helix angle,

tan Ļ† = Coefficient of friction between the threaded rod and the coupler nut,Ā and

dp = Pitch diameter or mean diameter of the threaded rod.

āˆ“ Shear stress produced by the torque,

Ļ„ = (T Ɨ dp)/ (2 Ɨ J)

Ā  Ā = [{P tan (Ī± + Ļ†) dp/2} Ɨ dp] / [{2 Ɨ Ļ€ (dp)^4} / 32]

Ā  Ā = [P tan (Ī± + Ļ†)Ā Ć— 8] / [Ļ€ (dp)^2]

Ā  Ā =Ā 8P [(tan Ī± + tan Ī±) / (1 – tan Ī±Ā tan Ī±)]/Ā [Ļ€ (dp)^2]

The usual values of tan Ī±, tan Ļ† and dp are as follows :

tan Ī± = 0.03, tan Ļ† = 0.2, and dp = 1.08 dc

Substituting these values in the above expression, we get

Ļ„ =Ā Ā 8P [(0.03Ā + 0.2) / (1 – 0.03Ā Ć—Ā 0.2)]/Ā [Ļ€ (1.08 dc)^2]

Ā  Ā = 8P / 4Ļ€ (dc)^2

Ā  Ā = P / 2A

Ā  Ā =Ā Ļƒt / 2

Since the threaded rod is subjected to tensile stress as well as shear stress, therefore maximumĀ principal stress,

Ļƒt (max) = (Ļƒt / 2) + {[{Ļƒt^2 + 4Ļ„^2}^0.5]/2}

Ā  Ā  Ā  Ā  Ā  Ā  Ā  Ā  Ā  Ā =Ā (Ļƒt / 2) + {[{Ļƒt^2 + Ļƒt^2}^0.5]/2} Ā  Ā  Ā  Ā  Ā  Ā  Ā  Ā (‘.’ Ļ„ = Ļƒt / 2)

Ā  Ā  Ā  Ā  Ā  Ā  Ā  Ā  Ā  Ā = 0.5Ā Ļƒt + 0.707Ā Ļƒt

Ā  Ā  Ā  Ā  Ā  Ā  Ā  Ā  Ā  Ā = 1.207Ā Ļƒt

Ā  Ā  Ā  Ā  Ā  Ā  Ā  Ā  Ā  Ā = 1.207 P / A

Giving a margin for higher coefficient of friction, the maximum principal stress may be taken asĀ 1.3 times the normal stress. Therefore for designing a threaded section, we shall take the design loadĀ as 1.3 times the normal load, i.e.Ā Design load, Pd = 1.3 P

The following procedure may be adopted in designing a turn-buckle :

1. Diameter of the rods

The diameter of the rods (d) may be obtained by considering the tearing of the threads of theĀ rods at their roots. We know that

Tearing resistance of the threads of the rod

=Ā Ļ€ (dc)^2Ā Ļƒt / 4

Equating the design load (Pd) to the tearing resistance of the threads, we have

Pd =Ā Ļ€ (dc)^2Ā Ļƒt / 4

where dc = Core diameter of the threads of the rod, and

Ļƒt = Permissible tensile stress for the material of the rod.

From the above expression, the core diameter of the threads may be obtained. The nominalĀ diameter of the threads (or diameter of the rod) may be found from Table 11.1, corresponding to theĀ core diameter, assuming coarse threads.

2. Length of the coupler nut

The length of the coupler nut (l) is obtained by considering the shearing of the threads at theirĀ roots in the coupler nut. We know that

Shearing resistance of the threads of the coupler nut

= (Ļ€ dc Ɨ l) Ļ„

where Ļ„ = Shear stress for the material of the coupler nut.

Equating the design load to the shearing resistance of the threads in the coupler nut, we have

Pd = (Ļ€ dc Ɨ l ) Ļ„

From this expression, the value of l may be calculated. In actual practice, the length of couplerĀ nut ( l ) is taken d to 1.25 d for steel nuts and 1.5 d to 2 d for cast iron and softer material nut. The lengthĀ of the coupler nut may also be checked for crushing of threads. We know that

Crushing resistance of the threads in the coupler nut

= (Ļ€/4) (d^2 – dc^2) (n) (l) (Ļƒc)

where Ļƒc = Crushing stress induced in the coupler nut, and

n = Number of threads per mm length.

Equating the design load to the crushing resistance of the threads, we have

Pd =Ā = (Ļ€/4) (d^2 – dc^2) (n) (l) (Ļƒc)

From this expression, the induced Ļƒc may be checked.

3. Outside diameter of the coupler nut

The outside diameter of the coupler nut (D) may be obtained by considering the tearing at theĀ coupler nut. We know that

Tearing resistance at the coupler nut

= (Ļ€/4) (D^2 – d^2) (Ļƒt)

where Ļƒt = Permissible tensile stress for the material of the coupler nut.

Equating the axial load to the tearing resistance at the coupler nut, we have

P =Ā (Ļ€/4) (D^2 – d^2) (Ļƒt)

From this expression, the value of D may be calculated. In actual practice, the diameter of theĀ coupler nut (D) is taken from 1.25 d to 1.5 d.

4. Outside diameter of the coupler

The outside diameter of the coupler (D2) may be obtained by considering the tearing of theĀ coupler. We know that

Tearing resistance of the coupler

=Ā (Ļ€/4) {(D2)^2 – (D1)^2} (Ļƒt)

where D1 = Inside diameter of the coupler. It is generally taken as (d + 6 mm), and

Ļƒt = Permissible tensile stress for the material of the coupler.

Equating the axial load to the tearing resistance of the coupler, we have

P =Ā (Ļ€/4) {(D2)^2 – (D1)^2} (Ļƒt)

From this expression, the value of D2 may be calculated. In actual practice, the outside diameterĀ of the coupler (D2) is taken as 1.5 d to 1.7 d. If the section of the coupler is to be made hexagonal orĀ rectangular to fit the spanner, it may be circumscribed over the circle of outside diameter D2.

5. The length of the coupler between the nuts (L) depends upon the amount of adjustmentĀ required. It is usually taken as 6 d.

6. The thickness of the coupler is usually taken as t = 0.75 d, and thickness of the coupler nut,Ā t1 = 0.5 d.

Reference A Textbook of a Machine Design by R.S. Khurmi and J.K. Gupta